(3x-5)=4x^2+8x+7

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Solution for (3x-5)=4x^2+8x+7 equation: 



(3x-5)=4x^2+8x+7

We move all terms to the left:

(3x-5)-(4x^2+8x+7)=0

We get rid of parentheses

-4x^2+3x-8x-5-7=0

We add all the numbers together, and all the variables

-4x^2-5x-12=0

a = -4; b = -5; c = -12;
Δ = b2-4ac
Δ = -52-4·(-4)·(-12)
Δ = -167
Delta is less than zero, so there is no solution for the equation

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